50 replies to this topic

[ChrisF-dude]

Is it safe to assume he took the hood off to clearly show the engine and bay? And didn't he say he put the larger rims on for a photo shoot, and usually runs MX5 rims? I'm not one for stickers, but he seems to have the goods to back up the stickers. I still like it a lot. It takes a LOT of work and pioneering to get it into a 3rd gen considering the mags are just putting themm into 96+ Civics, and one or two 2nd gen CRXs. I give him props. More work than I can do.

[G AE82]

Just so everyone knows, I didn't choose to take the bonnet off, the photographer wanted the bonnet off for lighting reasons because the engine bay is the centre piece. The stickers are also not a choice as they are advertising for my tuner who sponsors me. No stickers and I don't get paid

[a3h87]

damn!! k20a+hondata..crazy .

[icebox187]

are you guys gonna turn this place into honda-tech, or, cant we all just get along lol..... nice swap man, got them axles figured out yet?

[a3h87]

was wonderin if you did write-up for the swap.hot ride

[mayhem019]

I'm curious about what kind of power this thing makes at the wheels to run 11 sec 1/4 mile... These cars are a lot lighter than most so its hard for me to determine.. Anyone have a guess?

[shadowboy]

I'm curious about what kind of power this thing makes at the wheels to run 11 sec 1/4 mile... These cars are a lot lighter than most so its hard for me to determine.. Anyone have a guess?

Power is proportional to m*s^2 / 2t

s = trap speed
t = ET
m = mass of vehicle.

If you take mass in kg, speed in m/sec, and time in sec, you'll get power in Watts.


power = work divided by time. work here is equal to the final kinetic energy minus initial kinetic energy [0]. kinetic energy is 1/2 mass times velocity squared.


Mind you, this will give you average power used to *accelerate the vehicle* (less aerodynamic drag & friction). The actual power will be more.

More information will yield more a more accurate estimate--at the expense of being more difficult to calculate (solving a second order nonlinear differential equation--such as the drag equation--is a nontrivial exercise).


Or you could just use your own timeslip as a reference. It takes about 8 times the horsepower to double your trap speed / half your ET.

Edited by shadowboy, 17 May 2007 - 02:28 PM.

[zakats]

Power is proportional to m*s^2 / 2t

s = trap speed
t = ET
m = mass of vehicle.

If you take mass in kg, speed in m/sec, and time in sec, you'll get power in Watts.
power = work divided by time. work here is equal to the final kinetic energy minus initial kinetic energy [0]. kinetic energy is 1/2 mass times velocity squared.
Mind you, this will give you average power used to *accelerate the vehicle* (less aerodynamic drag & friction). The actual power will be more.

More information will yield more a more accurate estimate--at the expense of being more difficult to calculate (solving a second order nonlinear differential equation--such as the drag equation--is a nontrivial exercise).
Or you could just use your own timeslip as a reference. It takes about 4 times the horsepower to double your trap speed.

Quiet you!

[shadowboy]

Quiet you!

Damnnit, you had to quote me before I fixed the mistake, didn't you?

[zakats]

it dont matter nun dangit, i aint gun have that theres mathmatical mumbo jumbo liberal hooha horses ayass in this heyere's establishment...

[eric87crx]

Sweet ride mein..i like it

[bobdragster]

OMG I just saw the comment I made in this thread a while back. Why have I not been shot? The car is badass.

[watzizzname]

Freakin' sweet!!


I'm sure its fast, and has tons of power... but the thing I'm most curious about is how badly it broke your bank. I mean... look at it, the car was worth it. I just want to know what it took.

[SHOGUNOVDDRK]

very nice bro...

a true inspiration for 3g owners in australia

[NWClassicHonda]

I love your car!